# What is the amount of charge in coulombs required to reduce 1 mole of kmno4 to mn2?

Contents

93×105C.

## How much charge is required for the reduction of 1 mole of MnO4 to Mn2+?

To reduce MnO4- to Mn2+ the required charge is 5 mole electrons.

## How many coulombs are required for the reduction of 1 mol of MnO4 − to Mn2 +?

93×105C.

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9. 65×106C.

## What is the quantity of Faraday’s needed to reduce 1 mole of ions in faintly alkaline medium?

Number of coulombs of current required to convert completely convert one mole of.

## How many coulombs are required for the reduction of 1 mole of cu2+ to Cu?

How much charge is required for the reduction of 1 mole of Cu^(2+) to Cu. =2×96500=193000C.

## How much charge is required for the reduction of 1 mole of MnO to MN?

Therefore, 5 mol of electrons are required to reduce 1 mol of MnO-4 ions).

93×105C.

1×96500 C.

## How much Coulomb charge is present on 1g ion of n3?

= 2.89 × 10^5 coulomb.

## How many coulombs are in an electric charge?

The coulomb (symbol: C) is the International System of Units (SI) unit of electric charge. Under the 2019 redefinition of the SI base units, which took effect on 20 May 2019, the coulomb is exactly 1/(1.602176634×1019) elementary charges.

coulomb
Atomic units 6.241509074e×1018

1. 93×105C.

9. 65×106C.

## How many Faradays of electricity is required to reduce 1 mole of mno4 ions to Mn 2 ions?

How many faradays are required to reduce 1 mol of MnO_4^(-) to Mn^(2+)? 5 moles of e-=5 Faradays.

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## How much electricity in terms of Faraday is produced by the oxidation of 1 mole of Zn?

So, for 1 mole of zinc ion, the number of electrons involved is 2 moles. We know that 1 F or 1 farad is the amount charge present in 1 mole of electrons. So, the total charge in the above reaction is 2F. Therefore, the quantity of electricity required to deposit one mole of zinc is 193000 coulombs.