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1 mole of H2SO4 produces 2 moles of H+ ions in solution. 1 mole of NaOH produces 1 mole of OH- ions in solution. Therefore you will need 2 moles of NaOH to neutralize the 2 moles of H+ ions in solution. you can clearly see that 1 mole of H2SO4 will react with 2 moles of NaOH.

## How many grams of NaOH are needed to neutralize the H2SO4?

how many grams of NaOH are needed to neutralize 50 grams of H2SO4?

## How many moles of H2SO4 are needed to neutralize 0.5 moles NaOH?

If you write the balanced equation, you will see that 2 moles of sodium hydroxide react with 1 mole of sulfuric acid to form 1 mole of sodium sulfate and 2 moles of water. Therefore it would take . 25 moles of sulfuric acid to react with .

## How many moles of NaOH react with 1 mole of H2SO4?

The ratio of NaOH to H2SO4 is 2:1. So you get 2 moles of NaOH for every 1 mole of H2SO4.

## How many moles of NaOH are required to neutralize?

A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.

## How many grams of NaOH are required to neutralize?

to convert from g NaOH to mol NaOH. = 1.48 g NaOH are needed to neutralize the acid.

## How many grams of NaOH are needed to neutralize 12.2 grams of benzoic acid?

So, thus in order to neutralize the 12.2 g of the benzoic acid, we need to take 4 g of the $NaOH$. Hence, the option (d) is correct.

## How many moles are required to neutralize?

Titrations. When hydrochloric acid is reacted with sodium hydroxide, an acid/base mole ratio of 1:1 is required for full neutralization. If instead the hydrochloric acid were reacted with barium hydroxide, the mole ratio would be 2:1. Two moles of HCl are required to completely neutralize one mole of Ba(OH)_{2}.

## How do you calculate moles needed to neutralize?

So, the solution will be neutralized when the number of moles of H^{+} equals the number of moles of OH^{–}.

- Step 1: Calculate the number of moles of OH
^{–}. - Molarity = moles/volume.
- moles = Molarity x Volume.
- moles OH
^{–}= 0.02 M/100 milliliters. - moles OH
^{–}= 0.02 M/0.1 liters. - moles OH
^{–}= 0.002 moles.

## How many moles of H2SO4 are required for the Neutralisation of NaOH?

1 mole of H2SO4 produces 2 moles of H+ ions in solution. 1 mole of NaOH produces 1 mole of OH- ions in solution. Therefore you will need 2 moles of NaOH to neutralize the 2 moles of H+ ions in solution. you can clearly see that 1 mole of H2SO4 will react with 2 moles of NaOH.

## How much 1.00 m NaOH is needed to neutralize the H2SO4 solution?

From this you can see that it takes 2 moles NaOH per 1mole H2SO4.

## How many moles of potassium hydroxide react with 1 mole of hydrochloric acid?

One mole of HCl reacts with one mole of KOH. 0.0025 moles of HCl react with 0.0025 moles of KOH.

## How many moles of H+ ions are there in 1 mole of H2SO4?

Now, after rounding off this value we will get 2g as the amount of hydrogen present in one mole of sulphuric acid, which is the required answer.

## How many moles of H2SO4 are required for the Neutralisation of 4l of 2n NaOH?

How many moles of h2so4 are required to neutralize 4 litre of 2n naoh solun? – Quora. 2 NaOH+ H2SO4 ===> Na2SO4 + 2H2O. From the above equation we come to know that 2- moles of NaOH will neutralise 1- mole of H2SO4. (98 x4)= 392-g of H2SO4.

## How many grams of H2SO4 are needed to neutralize completely?

One mole of H2SO4 (98 grams) will neutralize two moles on NaOH (40 grams per mole).

## How many moles of KOH are needed to neutralize 1.5 moles H2SO4?

1 Expert Answer

The balanced reaction is as written. 2 KOH + H2SO4 —> 2 H2O + K2SO4. 1.5 moles H2SO4 ( 2 KOH/1 H2SO4) = 3 moles of KOH.